Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 16:43Z
10y² + 5y + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
327K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8t² + 6t + 7 = 0
det| 9 4 ; 1 10 | = 86
459K
d/dω [ω^5] = 5ω^4
ΔS ≥ 0
det| 3 7 ; 2 4 | = -2
323K
∑_{k=1}^{n} k = n(n+1)/2