Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 04:11Z
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
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e^{i\pi} + 1 = 0
∫₀^∞ e^(-n²) dn = √π / 2
det| 6 4 ; 6 7 | = 18
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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\lim_{n\to 0} \frac{\sin n}{n} = 1
det| 7 4 ; 4 8 | = 40
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λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂