Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 17:10Z
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
132K
5φ² + 6φ + 6 = 0
\frac{7}{1} \sum_{i=1}^{n} i^{2}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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e^{i\pi} + 1 = 0
det| 10 7 ; 3 11 | = 89
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