Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-17 22:36Z
∇²γ = 0
9y² + 1y + 3 = 0
ω = 2πf
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
162K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
92K
\lim_{n\to 0} \frac{\sin n}{n} = 1
∇²r = 0
d/dr [r^11] = 11r^10