Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:29Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
∫₀^∞ e^(-β²) dβ = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 3 7 ; 2 4 | = -2
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2y² + 4y + 4 = 0
det| 9 4 ; 1 10 | = 86
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∑_{k=1}^{n} k = n(n+1)/2
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