Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 06:41Z
∇²t = 0
det| 11 9 ; 0 12 | = 132
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∫₀^∞ e^(-z²) dz = √π / 2
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det| 5 8 ; 6 6 | = -18
det| 7 4 ; 4 8 | = 40
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∑_{k=1}^{n} k = n(n+1)/2
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d/dy [y^12] = 12y^11
7γ² + 2γ + 5 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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