Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 16:23Z
10y² + 5y + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
476K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
59K
∫₀^∞ e^(-n²) dn = √π / 2
232K
8t² + 6t + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
23K
d/dω [ω^5] = 5ω^4
det| 9 6 ; 0 10 | = 90
435K
ΔS ≥ 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
323K
det| 9 4 ; 1 10 | = 86
112K
7t² + 2t + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O