Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 23:58Z
∇²x = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
132K
7β² + 4β + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
170K
E = mc²
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
52K
2r² + 4r + 7 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
393K
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
82K
∂z/∂t = 7z
det| 7 4 ; 4 8 | = 40
391K