Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 19:23Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
170K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
97K
\oint_C \vec{F}\cdot d\vec{r} = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∇²ω = 0
∂y/∂β = 3y
∑_{k=1}^{n} k = n(n+1)/2
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det| 9 4 ; 1 10 | = 86
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9n² + 3n + 4 = 0
det| 9 7 ; 3 10 | = 69
391K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O