Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:39Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
132K
2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2y² + 4y + 4 = 0
∫₀^∞ e^(-n²) dn = √π / 2
346K
det| 4 7 ; 2 5 | = 6
130K
det| 1 1 ; 3 2 | = -1
82K
∑_{k=1}^{n} k = n(n+1)/2
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