Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 06:41Z
∇²t = 0
det| 5 6 ; 1 6 | = 24
327K
det| 5 8 ; 6 6 | = -18
det| 7 4 ; 4 8 | = 40
59K
d/dy [y^12] = 12y^11
det| 4 7 ; 2 5 | = 6
459K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
323K
∫₀^∞ e^(-t²) dt = √π / 2
112K
∑_{k=1}^{n} k = n(n+1)/2
2K