Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 23:49Z
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
75K
∫₀^∞ e^(-β²) dβ = √π / 2
132K
7β² + 4β + 7 = 0
E = mc²
2r² + 4r + 7 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
346K
det| 9 9 ; 5 10 | = 45
130K
∑_{k=1}^{n} k = n(n+1)/2
82K