Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 05:53Z
det| 3 2 ; 6 4 | = 0
ω = 2πf
det| 6 9 ; 7 7 | = -21
∫₀^∞ e^(-ω²) dω = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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CH₄ + 2O₂ → CO₂ + 2H₂O
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ΔS ≥ 0
5ω² + 4ω + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2