Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 19:04Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
75K
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
97K
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 6 6 ; 2 7 | = 30
52K
∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
346K
∂y/∂β = 3y
det| 9 4 ; 1 10 | = 86
82K
9n² + 3n + 4 = 0
det| 4 8 ; 0 5 | = 20
391K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O