Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 17:10Z
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
132K
5φ² + 6φ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
170K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
52K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
130K