Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 19:24Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
132K
F = ma
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 4 ; 4 8 | = 40
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∇²ω = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∂y/∂β = 3y
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
130K
∑_{k=1}^{n} k = n(n+1)/2
82K
9n² + 3n + 4 = 0
10φ² + 9φ + 5 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O