Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 19:27Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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F = ma
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 7 4 ; 4 8 | = 40
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
130K
∫₀^∞ e^(-n²) dn = √π / 2
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
391K