Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 23:39Z
\frac{2}{6} \sum_{i=1}^{n} i^{2}
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
217K
2γ² + 2γ + 5 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
280K
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p
det| 7 4 ; 4 8 | = 40
62K
\frac{8}{5} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
127K
F = ma