Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 04:08Z
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
det| 7 8 ; 6 8 | = 8
476K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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∫₀^∞ e^(-n²) dn = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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det| 3 1 ; 7 4 | = 5
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det| 6 4 ; 6 7 | = 18
CH₄ + 2O₂ → CO₂ + 2H₂O
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det| 7 4 ; 4 8 | = 40
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\lim_{n\to 0} \frac{\sin n}{n} = 1
10ω² + 7ω + 7 = 0
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
11ψ² + 9ψ + 2 = 0