Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:14Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
75K
2y² + 6y + 4 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
170K
\frac{12}{7} \sum_{i=1}^{n} i^{2}
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2y² + 4y + 4 = 0
\frac{11}{9} \sum_{i=1}^{n} i^{2}
393K
∫₀^∞ e^(-β²) dβ = √π / 2
346K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
82K