Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 00:55Z
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
75K
det| 5 6 ; 1 6 | = 24
132K
det| 2 9 ; 2 3 | = -12
∑_{k=1}^{n} k = n(n+1)/2
170K
PV = nRT
\binom{n}{k} = \frac{n!}{k!(n-k)!}
52K
6n² + 5n + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
393K
det| 3 8 ; 6 4 | = -36
det| 7 4 ; 4 8 | = 40
82K
λ = h/p
d/dβ [β^12] = 12β^11
\frac{12}{3} \sum_{i=1}^{n} i^{2}
e^{i\pi} + 1 = 0