Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:57Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
170K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 12 1 ; 5 13 | = 151
52K
det| 9 4 ; 1 10 | = 86
344K
2y² + 4y + 4 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
346K
∑_{k=1}^{n} k = n(n+1)/2
82K