Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 23:37Z
\frac{2}{6} \sum_{i=1}^{n} i^{2}
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
102K
2γ² + 2γ + 5 = 0
det| 5 9 ; 7 6 | = -33
280K
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p
\frac{8}{5} \sum_{i=1}^{n} i^{2}
\frac{7}{1} \sum_{i=1}^{n} i^{2}
127K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
472K
F = ma