Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:54Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
∫₀^∞ e^(-ω²) dω = √π / 2
170K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2y² + 4y + 4 = 0
det| 9 9 ; 5 10 | = 45
393K
∑_{k=1}^{n} k = n(n+1)/2
346K
\oint_C \vec{F}\cdot d\vec{r} = 0