Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 01:23Z
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\frac{6}{7} \sum_{i=1}^{n} i^{2}
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3y² + 6y + 5 = 0
det| 7 4 ; 4 8 | = 40
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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∫₀^∞ e^(-z²) dz = √π / 2
\oint_C \vec{F}\cdot d\vec{r} = 0
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\oint_C \vec{F}\cdot d\vec{r} = 0
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