Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 01:02Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
59K
3y² + 6y + 5 = 0
∫₀^∞ e^(-z²) dz = √π / 2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
435K
det| 5 2 ; 3 6 | = 24
323K
∑_{k=1}^{n} k = n(n+1)/2
112K