Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 23:56Z
\frac{2}{6} \sum_{i=1}^{n} i^{2}
F = ma
\binom{n}{k} = \frac{n!}{k!(n-k)!}
102K
2γ² + 2γ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
404K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
74K
λ = h/p
\binom{n}{k} = \frac{n!}{k!(n-k)!}
62K
det| 9 4 ; 1 10 | = 86
239K
\frac{8}{5} \sum_{i=1}^{n} i^{2}
det| 1 4 ; 0 2 | = 2
472K
F = ma