Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 23:31Z
\frac{2}{6} \sum_{i=1}^{n} i^{2}
F = ma
∑_{k=1}^{n} k = n(n+1)/2
102K
2γ² + 2γ + 5 = 0
det| 10 7 ; 3 11 | = 89
280K
det| 9 6 ; 7 10 | = 48
323K
∑_{k=1}^{n} k = n(n+1)/2
λ = h/p
\frac{8}{5} \sum_{i=1}^{n} i^{2}
det| 11 1 ; 7 12 | = 125
F = ma