Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 12:24Z
∑_{k=1}^{n} k = n(n+1)/2
2ω² + 3ω + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
232K
λ = h/p
det| 10 3 ; 4 11 | = 98
23K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
459K
det| 1 1 ; 3 2 | = -1
det| 9 4 ; 1 10 | = 86
435K
∑_{k=1}^{n} k = n(n+1)/2
84K
e^{i\pi} + 1 = 0