Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 12:57Z
∑_{k=1}^{n} k = n(n+1)/2
det| 2 4 ; 4 3 | = -10
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∑_{k=1}^{n} k = n(n+1)/2
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2ω² + 3ω + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
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λ = h/p
det| 7 4 ; 4 8 | = 40
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det| 1 1 ; 3 2 | = -1
e^{i\pi} + 1 = 0
det| 9 2 ; 4 10 | = 82
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