Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 04:06Z
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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e^{i\pi} + 1 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
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∫₀^∞ e^(-n²) dn = √π / 2
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
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det| 6 4 ; 6 7 | = 18
\lim_{n\to 0} \frac{\sin n}{n} = 1
λ = h/p
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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