Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 21:08Z
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
132K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 4 1 ; 1 5 | = 19
CH₄ + 2O₂ → CO₂ + 2H₂O
393K
det| 9 5 ; 5 10 | = 65
det| 7 1 ; 4 8 | = 52
d/dθ [θ^5] = 5θ^4
∇²x = 0