Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 16:42Z
10y² + 5y + 7 = 0
det| 7 4 ; 4 8 | = 40
327K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\binom{n}{k} = \frac{n!}{k!(n-k)!}
232K
8t² + 6t + 7 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
459K
d/dω [ω^5] = 5ω^4
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
84K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
323K
∑_{k=1}^{n} k = n(n+1)/2
7t² + 2t + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}