Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 04:46Z
2ψ² + 8ψ + 4 = 0
∂y/∂ψ = 5y
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
52K
∇ × E = −∂B/∂t
det| 7 4 ; 4 8 | = 40
393K
∑_{k=1}^{n} k = n(n+1)/2
d/dz [z^10] = 10z^9
det| 7 4 ; 1 8 | = 52
det| 4 4 ; 7 5 | = -8
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2