Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 16:39Z
10y² + 5y + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
476K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 6 6 ; 5 7 | = 12
232K
8t² + 6t + 7 = 0
d/dω [ω^5] = 5ω^4
ΔS ≥ 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
323K
∑_{k=1}^{n} k = n(n+1)/2
7t² + 2t + 3 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O