Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 19:01Z
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
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det| 7 6 ; 1 8 | = 50
det| 2 4 ; 4 3 | = -10
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d/dn [n^9] = 9n^8
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
∫₀^∞ e^(-β²) dβ = √π / 2
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