Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:28Z
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
75K
2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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∫₀^∞ e^(-n²) dn = √π / 2
344K
2y² + 4y + 4 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
393K
det| 2 4 ; 4 3 | = -10
130K
∑_{k=1}^{n} k = n(n+1)/2
391K