Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:31Z
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
75K
2y² + 6y + 4 = 0
∫₀^∞ e^(-r²) dr = √π / 2
170K
\frac{11}{9} \sum_{i=1}^{n} i^{2}
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∫₀^∞ e^(-n²) dn = √π / 2
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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
344K
2y² + 4y + 4 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
393K
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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