Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:39Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
132K
2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 7 4 ; 4 8 | = 40
52K
2y² + 4y + 4 = 0
det| 3 3 ; 4 4 | = 0
393K
∑_{k=1}^{n} k = n(n+1)/2
346K
det| 1 1 ; 3 2 | = -1
130K