Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 12:27Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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det| 7 4 ; 4 8 | = 40
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2ω² + 3ω + 1 = 0
det| 3 3 ; 4 4 | = 0
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λ = h/p
∑_{k=1}^{n} k = n(n+1)/2
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det| 1 1 ; 3 2 | = -1
Fe₂O₃ + 3CO → 2Fe + 3CO₂
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