Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 01:19Z
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
476K
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
232K
3y² + 6y + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
459K
∫₀^∞ e^(-z²) dz = √π / 2
Fe₂O₃ + 3CO → 2Fe + 3CO₂
435K
det| 7 4 ; 4 8 | = 40
84K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
112K
e^{i\pi} + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
2K
ω = 2πf
d/dφ [φ^3] = 3φ^2