Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:55Z
∑_{k=1}^{n} k = n(n+1)/2
det| 2 4 ; 4 3 | = -10
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2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
344K
2y² + 4y + 4 = 0
det| 7 4 ; 4 8 | = 40
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det| 11 9 ; 0 12 | = 132
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\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
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