Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 04:07Z
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
327K
e^{i\pi} + 1 = 0
∫₀^∞ e^(-n²) dn = √π / 2
det| 9 4 ; 1 10 | = 86
459K
det| 6 4 ; 6 7 | = 18
\lim_{n\to 0} \frac{\sin n}{n} = 1
10ω² + 7ω + 7 = 0