Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-18 02:52Z
2t² + 6t + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
212K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\frac{6}{7} \sum_{i=1}^{n} i^{2}
217K
det| 9 7 ; 0 10 | = 90
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
323K
d/dα [α^11] = 11α^10
\binom{n}{k} = \frac{n!}{k!(n-k)!}
404K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
62K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
239K
∑_{k=1}^{n} k = n(n+1)/2
127K
det| 9 4 ; 1 10 | = 86
472K