Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 01:16Z
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
232K
3y² + 6y + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
23K
∫₀^∞ e^(-z²) dz = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
435K
det| 9 4 ; 1 10 | = 86
84K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
98K
ω = 2πf