Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:09Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
170K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 10 3 ; 4 11 | = 98
52K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
344K
2y² + 4y + 4 = 0
\lim_{t\to 0} \frac{\sin t}{t} = 1
393K
∫₀^∞ e^(-ω²) dω = √π / 2
346K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
82K