Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 04:13Z
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
476K
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
59K
∫₀^∞ e^(-n²) dn = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
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det| 6 4 ; 6 7 | = 18
CH₄ + 2O₂ → CO₂ + 2H₂O
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\lim_{n\to 0} \frac{\sin n}{n} = 1
det| 5 3 ; 2 6 | = 24
323K
10ω² + 7ω + 7 = 0
λ = h/p
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
11ψ² + 9ψ + 2 = 0
6β² + 5β + 5 = 0