Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-20 06:34Z
∇²t = 0
det| 5 8 ; 6 6 | = -18
∑_{k=1}^{n} k = n(n+1)/2
232K
d/dy [y^12] = 12y^11
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
23K
7γ² + 2γ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
435K
det| 9 4 ; 1 10 | = 86
84K
det| 3 8 ; 0 4 | = 12
∑_{k=1}^{n} k = n(n+1)/2
323K
E = mc²