Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 17:59Z
F = ma
∑_{k=1}^{n} k = n(n+1)/2
75K
5φ² + 6φ + 6 = 0
∫₀^∞ e^(-n²) dn = √π / 2
97K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
e^{i\pi} + 1 = 0
det| 1 1 ; 3 2 | = -1
393K
det| 7 2 ; 5 8 | = 46
E = mc²
2H₂ + O₂ → 2H₂O
det| 9 4 ; 3 10 | = 78
\lim_{φ\to 0} \frac{\sin φ}{φ} = 1