Math Dump /sym/bb7c3c
id=1 · host=ap.findroms.cloud · 2026-10-19 01:32Z
∑_{k=1}^{n} k = n(n+1)/2
2y² + 6y + 4 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 9 4 ; 1 10 | = 86
52K
∫₀^∞ e^(-β²) dβ = √π / 2
344K
2y² + 4y + 4 = 0
det| 1 4 ; 0 2 | = 2
393K
∑_{k=1}^{n} k = n(n+1)/2
346K